1) You will be doing an experiment at a new research
farm. You are
considering using a plot size of 0.2 ha (hectares, 0.2 ha = 2,000 m^2). The
only previous data about plot-plot variability on this farm is from a study using 0.5 ha plots. Those data
suggest that the s.d. between 0.5 ha plots is 3.1 kg/ha.
a)
What s.d. (between your 0.2 ha plots) would you expect to see?
b) Your study will compare 6 treatments, using a 1 way ANOVA. You
are given a choice of using 24 0.2 ha plots
(i.e. 4 per treatment) or 12 0.5 ha plots (i.e. 2 per treament).
Please consider s.e. of a treatment mean and error d.f. Does the
choice of plot size make much difference? Which plot
size is better statistically? Explain your choice.
Hint: You do not
need to calculate power, but you should support your choice
numerically.
2) Consider an experiment like the salinity experiment, where containers are randomly assigned to one of two treatments and measurements are taken on k plants per container. Previous studies suggest that sigma^2(containers) = 0.49 and sigma^2(plants) = 6.76. These are the variance components for containers and plants. You are told to make sure that your experiment provides a s.e. of a treatment mean that is less than 0.5.
a) If you measure P=2 plants per container and C=16 containers
per treatment, what is the s.e. of the mean?
b) If you measure P=5 plants per container and C=8 containers
per treatment, what is the s.e. of the mean?
c) Does either design satisfy the precision requirement
(i.e. s.e. < 0.5).
d) If the major cost in your study was the cost of measuring a
plant, which design should you use? Explain briefly.
e) If the major cost in your study was the space for a container
(e.g. on a greenhouse bench), which design should you use? Explain
briefly.
f) Calculate the se of the mean for P=2 plants and C=1 container.
g) Calculate the
variance between containers when two plants are measured per
container by squaring your answer from (f).
Is this the same as the variance component between containers given
at the begining of the problem (sigma^2(containers) = 0.49)?
Explain why or why not.
Please do problem 3 by hand.
3) The following data come from a study of rice yields in response
to elevated atmospheric CO2. The data considered here are only from
the 'ambient CO2' treatment. This treatment is applied to 8
fields. Grain yield is measured on three subsamples per field.
The response is log transformed yield (g/m2).
There were a total of 24 observations. The goal is to estimate the
variance component for fields, sigma^2_F, and the variance
components for subsamples, sigma^2_S.
Here is part of the ANOVA table:
| Source | d.f. | MS | Expected MS |
|---|---|---|---|
| Fields | 0.0321 | sigma^2_S + 3 sigma^2_F | |
| Error | 0.0012 | sigma^2_S |
a) Fill in the d.f. for fields and for subsamples.
b) Estimate the variance components, sigma^2_F and sigma^2_S.
c) Test the hypothesis that the field variance component
(sigma^2_F) is zero.
d) Without doing any calculations, will increasing the number of
subsamples per field to 6 be useful, in the sense of substantially
decreasing the s.e. of the mean yield? Briefly explain.