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Deflections - Method of Virtual Work
Rotation of a Beam - Superposition
problem statement
Using the same structure as used in the Beam Deflection examples, determine the rotation at A of the beam shown in the figure below using the method of Superposition. The modulus of elasticity (E) and the moment of inertia (I) are constant for the entire beam.
Note: The colors of the loads and moments are used to help indicate the contribution of each force to the deflection or rotation being calculated. The moment diagrams show the moments induced by a load using the same color as the load.
Figure 1 - Beam structure to analyze
Calculate the support reactions (caused by the applied loads) using the following relationships:
Check these reactions by summing the vertical forces.
The resulting system,
Figure 2 - Beam structure with support reactions
Using the method of superposition, draw a moment diagram for each separate load applied to the beam.
The resulting moment diagram can then be calculated by solving for each applied load separately and adding the results.
Note: The centroid of each area is indicated by the numbered arrow and dot.
i) Moment diagram due to the 56 ft-k concentrated moment at A,
Figure 3 - Moment diagram due to 56 ft-k moment
ii) Moment diagram due to the 2 k/ft applied load,
Figure 4 - Moment diagram due to 2 k/ft applied load
iii) Moment diagram due to the 6k applied load at end C,
Figure 5 - Moment diagram due to 6 k applied load
Notice that the resultant moment diagram is equal to the sum of these three diagrams.
Figure 6 - Resultant moment diagram
Apply the virtual load at the point of interest in the desired direction. In this case, we want to know the rotation at point A. Therefore, apply a unit moment at point A in the positive (clockwise) direction.
Figure 7 - Beam structure with virtual unit load applied
Following the same procedure used previously, calculate the support reactions (caused by the virtual load) using the following relationships:
Check these reactions by summing the vertical forces.
The resulting system,
Figure 8 - Reactions due to virtual unit load
Determine the moment diagram due to the virtual load using the same method as used to find the moment diagrams for the applied loads.
Moment diagram due to the virtual load using superposition.
Figure 9 - Moment diagram due to virtual unit load
Once the "real" moment diagrams are determined, calculate the area enclosed by each moment diagram and determine the location of the centroid of each of these areas.
| Area No. | Area/EI (k-ft2/EI) | Location of centroid from support (ft) |
| 1. | 1/2x-56x20/EI=-560/EI | X1 = 1/3x20 = 6.67 |
| 2. | 2/3x20x100/EI=1333.33/EI | X2 = 1/2x20 = 10 |
| 3. | 1/2x20x-36/EI=-360/EI | X3 = 1/3x20 = 13.33 |
| 4. | 1/2x6x-36/EI=-108/EI | X4 = 1/3x6 = 2 |
Determine the values - heights (hi) - on the virtual moment diagram (m) at the centroids of the moments due to the real loads. This is needed to carry out the integration by using the equation given in the introduction,

Heights and locations by superposition.
Figure 10 - Heights of virtual moment diagram
Integrate the equation
by using the visual integration approach.
Multiply the areas of the "real" moment diagram by the heights found in the virtual moment diagram and add them together.
| Area No. | Area (a) from M diagram (k-ft2/EI) |
Height (h) from m diagram (ft-k) |
Ai*hi (k2-ft3/EI) |
| 1. | -560/EI | 2/3 | -373.33/EI |
| 2. | 1333.33/EI | 1/2 | 666.67/EI |
| 3. | -360/EI | 1/3 | -120/EI |
| 4. | -108/EI | 0 | 0/EI |
| Total | 173.33/EI | ||
Since EI is constant throughout the structure, the total rotation at A equals +173.33 k2-ft3/EI.
The positive sign indicates that the rotation is in the same direction as the unit moment applied at A - therefore the rotation is in the clockwise direction.
If values of E and I are specified, the vertical deflection at C in inches can be determined. For example, let E = 29,000 ksi, I = 144 in4, and Q = 1 ft-k, then

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